## IF/THEN statement for Numbers

3095 Views 9 Replies Latest reply: Apr 16, 2014 7:12 AM by dvo247
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Aug 21, 2012 4:35 PM

I am trying to write an IF/THEN statement in Numbers, and here's the problem:

Column N displays tons: <8 costs \$215, 8 or greater costs \$280.  I need to write an IF/THEN statement to give the monetary total per unit based on tonnage instead of trying to hand-jam it.

 Tonnage Impact Service Group Quarter 1 Cooling Season Start-up (April) Impact Service Group Quarter 2 Cooling Season Inspection (July) Impact Service Group Quarter 3 Heating Season Start-up (October) Impact Service Group Quarter 4 Heating Inspection (January) Totals per Store 15 \$280 (more than 8) 15 \$280 40 \$280 5 \$215 (less than 8)

Need this formula for work; project to turn in by COB tomorrow

MacBook Pro, iOS 5.1.1
• Level 6 (10,765 points)
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Aug 21, 2012 4:39 PM (in response to tessrie)

=IF(N<8,215,280)

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Nov 10, 2012 10:23 AM (in response to Badunit)

I have a similar question involving an even more complex if/then statement.  Depending upon the price entered in Column A, I want Column B to display a percentage of the value of A.  But the percentage isn't straightforward..it depends on the value of Column A.  In laymen's terms it would look like this:

IF (Column A) is LESS than \$50, THEN 15%(A)

IF (A) is between 50.01-100, THEN 10%(A)

IF (A) is GREATER than 100.01, THEN 5%(A)

Is this possible?

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Nov 10, 2012 12:42 PM (in response to fan4bronco)

Try this:

=IF(A<=50,0.15*A,IF(A<=100,0.1*A,0.05*A))

• Level 7 (29,095 points)
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Nov 10, 2012 10:56 PM (in response to fan4bronco)

You can also attack it from the opposite direction to that suggested by Jeff:

IF(A>100,0.05*A,IF(A>50,0.1*A,0.15*A))

Regards,

Barry

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Nov 11, 2012 9:14 AM (in response to Jeff Shenk)

This worked like a charm, and I was even able to add a few more IF/THEN statements to the formula.  Thanks so much for helping a Numbers novice.

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Apr 15, 2014 7:13 PM (in response to Barry)

Hey if im trying to use multiple ranges for example if projections are less then 80,000 then 2, if greater then 80,000 then 3, if greater then 84,000 then 4. it works from below 80 to above 80 but once i go above 84 it keeps displaying 3. Any thoughts, thats my formula below?

IF(C1<80000,2,IF(C1≥80000,3,IF(C1>84000,4)

• Level 7 (29,095 points)
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Apr 15, 2014 10:31 PM (in response to dvo247)

Hi dvo,

The formula is working correctly. Any value that is greater than 84000 will already have been tested and found greater than 80000. Since C1≥80000 it TRUE, the formula will return 3, and will not test C1>84000.

Existing: IF(C1<80000,2,IF(C1≥80000,3,IF(C1>84000,4)

Revised: IF(C1>84000,4,IF(C1>=80000,3,2)

Note that testing for C1<80000 is redundant. If C1 is not greater than 84000 and is not equal to or greater than 80000, then it must be less than 80000.

Regards,

Barry

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Apr 15, 2014 10:36 PM (in response to fan4bronco)

Hi fan,

"I was even able to add a few more IF/THEN statements to the formula."

Once you get beyond three nested IFs, you should be looking at a LOOKUP table and one of the LOOKUP functions, rather than a string of IFs.

Regards,

Barry

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Apr 16, 2014 7:12 AM (in response to Barry)

Awesome thank you!!

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