5 Replies Latest reply: Nov 21, 2012 2:13 PM by nerak102
nerak102 Level 1 Level 1 (0 points)

I have done this straigthforward piece of La-tex and the equations further down have become smaller for some reason.

How can I stop this happening?

Or have I inadvertently done something to cause this to happen?

 

Screen Shot 2012-11-13 at 15.39.26.png


iPhone 4, iOS 6
  • 1. Re: Prevent Equations size changing?
    nerak102 Level 1 Level 1 (0 points)

    Here is the picture, which seems to have disappeared.Screen Shot 2012-11-13 at 15.39.26.png

  • 2. Re: Prevent Equations size changing?
    léonie Level 9 Level 9 (51,655 points)

    Why not place all three equations in one block, with

    \begin{aligned}
    9 && < && 15 && < && 16 \\
    \sqrt{9} && < && \sqrt{15} && < && \sqrt16 \\
    3 && < && \sqrt{15} && < &&4
    \end{aligned
    }

     

    This should prevent the lower equations from shrienking.


  • 3. Re: Prevent Equations size changing?
    nerak102 Level 1 Level 1 (0 points)

    They are all in one block using \begin{aligned} etc.

    I use \text to enter the text parts.

    Thanks for your reply.

  • 4. Re: Prevent Equations size changing?
    léonie Level 9 Level 9 (51,655 points)

    Can you post the LaTeX code of the equation, please?

     

    When I try to recreate your equation, I cannot recreate the decrease insize.

  • 5. Re: Prevent Equations size changing?
    nerak102 Level 1 Level 1 (0 points)

    Here is a good example

    \begin{aligned}\text {Differentiation of}\,x^2+3xy+4y^2=58\\

    2x+3y+3x\frac{dy}{dx}+8y{dy}{dx}&=0\\

    (3x+8y)\frac{dy}{dx}+2x+3y&=0\\

    (3x+8y)\frac{dy}{dx}&=-(2x+3y)\\

    \frac{dy}{dx}&=-\frac{(2x+3y)}{(3x+8y)}\\

    \text{at the point}\,\,(2,\,3)\,x=2,\,y=3\quad \frac{dy}{dx}&=-\frac{(4+9)}{6+24}\\

    &=-\frac{13}{30}\\

    \text{if gradient is}\,m\,\text{gradient of normal is}\,&=\frac{-1}{m}\\

    \frac{-1}{\frac{-13}{30}}=-\frac{1}{1}\div-\frac{13}{30}&=-\frac{1}{1}\times-\fr ac{30}{13}=\frac{30}{13}\\

    \text{For equation if line through}\,\,(2,\,3)\\

    \frac{y-3}{x-2}&=\frac{30}{13}\\

    13y-39&=30x-60\\

    30x-13y-21&=0

    \end{aligned}