Clearing a folder with dovecot

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Level 1

14 points

Clearing a folder with dovecot

I know a lot less about dovecot than about cyrus, so I'm sure there's a straightforward answer out there for this. The Apple documentation for the mail server talks about emptying the junkmail and notjunkmail folders nightly, but there's no pointer to how to do that.

When I try 'dovecotd --exec-mail ext /usr/libexec/dovecot/expire-tool', which is what looked like the right command, I get:

Error: read(/private/var/run/dovecot/dict-server) failed: Remote disconnected

I do have expire and expire_dict set.

Is expire-tool the right thing to use? Is there anything in the Apple docs that talks about doing this? If not it seems like a big oversight...

Thanks.

Kevin Brock

Mac Mini, Mac OS X (10.6.4)

Posted on Jun 30, 2010 12:21 PM

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Answer 1

kevinbrock Author

Level 1

14 points

Jun 30, 2010 5:31 PM in response to kevinbrock

Well, first part of the answer--it looks like the dovecot shipped with the 10.6 server isn't compiled with the --with-db option. It looks like that's necessary to use the expire plugin. I'm seeing the errors:

/var/log/system.log:Jun 30 17:27:43 ariel dovecot[10540]: dict: Unknown dict module: db
/var/log/system.log:Jun 30 17:27:43 ariel dovecot[10540]: dict: Failed to initialize dictionary 'expire'

Now the question is: Are there any other dict formats that expire can use? Am I reading this error incorrectly?

Why would Apple ship extensions that don't work with the version of the server they shipped?

Kevin

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Answer 2

KennethL

Level 1

0 points

Jul 4, 2010 6:40 AM in response to kevinbrock

I modified the /etc/mail/spamassassin/learn junkmail by adding

&& rm -f "$file"

at the end of line 104:

sudo -u _amavisd $SA LEARNPATH --dbpath $DB_PATH --spam --no-sync < "

and 114:

sudo -u _amavisd $SA LEARNPATH --dbpath $DB_PATH --ham --no-sync < " > /dev/null && rm -f "$file"

looks like this forum software does something strange when using the sign "less than" and "greater than" above where it should say "$file" between the two.

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