Not sure that can be done with a Pivot Table, as my explorations haven't entered that neighbourhood. Not too difficult using formulas, though.
You've given no information regarding the range of the individual numbers, so I've used the values possible on a throw of a single die (1-6), and arranged the 90 numbers in rows of 6, matching the quantity in your description.

Above is the table as displayed.
Columns H to M are hidden to keep the visual size of the table relatively small and to reduce the probability of accidentally damaging the formula in these cells. As seen below, though, the cells in these hidden columns contain the key formula that determines if each cell in columns B to G contains an Even or an Odd number, then expresses the result with the letters E or O.

The formulas in columns N and O use COUNTIF to count the number of Os or Es in their row:
N2: COUNTIF($H2:$M2,"O")
Fill right to O2
Then select both cells and fill down to Row 16
The bottom row of the table (17) is a Footer Row. The SUM formulas in columns N and O add the numbers in their column to display the total number of Odd and Even numbers in the respective columns.
N17: SUM(N2:N16)
O17: SUM(O2:O16)
For the example, I used this formula, entered in B2, then filled down and right to G16:
B2: =RANDBETWEEN(1,6)
In your case, you'll be entering observed data, rather than creating sample 'data' with a formula.
Regards,
Barry