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Hello,
I want to create some smart albums where I collect photo's with a specific pixel size. For example 7 MP photo's and 9 MP photo's. I see in the EXIF info only pixel height ad pixel width sizes, and what I need is the height x width pixel sizes.
Is this search option available in Aperture?
iMac (21.5-inch Late 2009), Mac OS X (10.7.3), AppleTV, iPhone 4S, iPad, MacBook
The search option is available in the Aperture metadata tags, not in the EXIF. In the Aperture tags you can search for "Pixel Size" or "Master Pixel Size". But you need to know the exact width and height to search for the product, like in the above example.
Regards
Léonie
The search option is available in the Aperture metadata tags, not in the EXIF. In the Aperture tags you can search for "Pixel Size" or "Master Pixel Size". But you need to know the exact width and height to search for the product, like in the above example.
Regards
Léonie
Thank you for your information, it helped me a bit. It is a pity that the product of height and width is not available in the search options. Because, the metadata field Pixel Size show this value between ().
Maybe writing a script will help me.
The info in between the parentheses isn't available (you can't find it using a filter). Afaik, there is no way to sort by image area without creating and populating a custom field.
Please recommend that this feature be added: "Aperture->Provide Aperture feedback".
(Sent from my magic glass - formatting not available.)
Thank Kriby, I will send in a feedback
Maybe writing a script will help me.
You are challenging me 🙂
Try the following script (but not on your main Aperture Library):
Open AppleScript Editor and paste it in; then select some images in Aperture and press the run button.
The script creates a custom field "NumberOfPixels" and writes the product of width and height to this field (for each of the selected images).
Can you go from here on your own? If not, post back.
Cheers
Léonie
tell application "Aperture"
set imageSel to (get selection)
if imageSel is {} then
error "Please select an image."
else
repeat with i from 1 to count of imageSel
tell item i of imageSel
set w to value of EXIF tag "PixelWidth"
set h to value of EXIF tag "PixelHeight"
set numPixels to (round (w * h)) as string
makenewcustom tagwith properties {name:"NumberOfPixels", value:numPixels}
end tell
end repeat
end if
end tell
Wow, I tried this on several photo's and it works great. I will test you script on a greater amount of photo's in my test library.
Haha…maybe you can assist Apple finishing Aperture 4 and build in some need features 😁
I am glad you like the script 🙂
Haha…maybe you can assist Apple finishing Aperture 4 and build in some need features
Hmmm, Aperture 4 might be a little more complicated than multiplying two numbers - let's wait and see what Apple will make of it, and perhaps we will be very, very surprised 😁
Maybe I'm missing something but
Gives me 8.0 mp images.
Maybe I'm missing something
Probably localization and/ or arithmetic rounding?
I tried both "Pixel Size includes 8.0" and "Pixel Size includes 8,0", both showed up as empty selections, even with the "Pixel Size" showing as "8,0" in the Metadata tab.
I am glad it works on your machine, for I seem to remember that I did previously exactly what you are showing, and it used to work.
Are you sure you have 8.0 mp images in the search scope? 😉
Don't know how arithmetic rounding could effect this but localization is a strong possibility. As I recall Aperture doesn't play nice with non-English (actually American) dates so I suppose it could be an issue here.
It would be interesting to see if you switch to American number representation if it would work for you. Those silly coma's where the periods should be can cause all sorts of trouble 😝
What if you just did 8, does it at least match any number in those fields? What about (8 just tried it here and it matched. Just curious.
regards
Frank,
do you find all 8.0 MP images with the above search rule or only a subset of them (trying to figure out if it is a floating point rounding problem)?
For me neither "Master Pixel Size" nor "Pixel Size" find any of the images - I tried all variants of syntax:
8.0, 8,0, 8.0 MP, 8,0 MP, (8.0 MP), (8,0 MP)
Léonie
Just tried setting my decimal seperator to , (comma) to see what would happen and 8.0 (8 dot 0) still matches but 8,0 (8 comma 0) does not match.
Are you sure you have 8.0 mp images in the search scope? 😉
do you really need to ask? 😁
Yes, I sure had.
It would be interesting to see if you switch to American number representation if it would work for you. Those silly coma's where the periods should be can cause all sorts of trouble 😝
Actually, the scientific number format is my default format - I have a custom "Language & Text" setting, but since I am drifting on an iCloud I have to reset my custom settings over and over again. The OS helpfully resets all my settings to german, as soon as it discovers I am in Germany. 😝
O.K. so I just reset the decimal separators again to ".", but no difference in Aperture.
I'll post back, after I logged off and on again.
Cheers
Léonie
P.S. Lt. Tuvok, what is your decimal point setting in the Netherlands?
We use comma als the decimal point.
No luck sofar, Frank.
Language & Text Formats set to "United States (Computer)" - or do you use simply "United States" ?
The smart album (defined at the top of the Library Albums section, all filters cleared) remains empty, even if I know there is at least one image of that size.
If I search for a single digit it is o.k.
I'll repair the library and try again.
Léonie
Create a smart album with x MP photo's
