I'm making an Xcode application, in Cocoa-Applescript, and I'de like to make it quit after it runs through the script. Is that possible? I've tried:
[[UIApplication sharedApplication] terminate];and
exit(0);but when I go to build it I get the error "Command /usr/bin/osacompile failed with exit code 1". How can I go about this?
Those look like (iOS) Objective-C and shell script statements. You can use NSApplication's terminate method or regular AppleScript:
current application's NSApp's terminate_(me)
tellmetoquit
I'm sorry I don't quit understand. I've put in the code into a run parameter at the end of my script "
on applicationDidFinishLaunching_ (aNotification)" but it stays open. Does it need a seperate parameter or am I missing something?
Applications in Xcode (AppleScript and otherwise) are typically event driven, so they do not terminate unless one of the standard ways such as the quit menu item is used, or there is a statement that quits the application. When using a program statement, you do need to use a valid AppleScriptObjC or regular AppleScript statement, or you will get a syntax error (the osacompile bit).
Also why are you using UIApplication? AppleScript-Objective-C should be OS X not IOS.
I was Googling it and saw that, decided I would try it. I don't have a lot of experience with Xcode...
Are you using the Cocoa AppleScript Application template when you made your new project in Xcode?
Maybe if you posted yout script it would help, you seem to be mixing up a few different idioms here.
As I said UIApplication is IOS and if you doing Cocoa Applescript you don;t call the Objective-C code using the bracket notation.
There is a lot of information in Xcode's Documentation and API Reference (assuming that you have downloaded some of the documentation sets). The language used is Objective-C though, so you'll need to do some conversions.
--
-- AppDelegate.applescript
-- Mc_Launcher
--
-- Created by Alex Lieflander on 13-04-16.
-- Copyright (c) 2013 Liefy. All rights reserved.
--
script AppDelegate
property parent : class "NSObject"
on applicationDidFinishLaunching_(aNotification)
--Edited out the string of commands, it was 600 lines...
end applicationDidFinishLaunching_
end script
Simple program. Starts puts up an Applescript dialog quirs when the dialog is dismissed.
--
-- AppDelegate.applescript
-- ASCTestQ
--
-- Created by Frank Caggiano on 4/17/13.
-- Copyright (c) 2013 Frank Caggiano. All rights reserved.
--
script AppDelegate
propertyparent : class"NSObject"
on applicationWillFinishLaunching_(aNotification)
-- Insert code here to initialize your application before any files are opened
display dialog "Running"
tellmetoquit
end applicationWillFinishLaunching_
on applicationShouldTerminate_(sender)
-- Insert code here to do any housekeeping before your application quits
return current application's NSTerminateNow
end applicationShouldTerminate_
endscript
If your application has no user interface, maybe Xcode is overkill. In that case, the Cocoa-AppleScript Applet template from the AppleScript Editor might be the better tool, since it recreates the usual handlers (such as run) but can also use various Cocoa methods. You will still need to manually quit the application, though.
Edit: a better description might be that it provides wrappers for the standard handlers, in that it will use them like a regular AppleScript if a handler is there.
To answer my own question, to quit an app with a line of code, I use:
tell current application to quit
Terminating an Xcode app after run?
