If in a range of numbers

'Contains' is what you're looking for.

However, if the range is contiguous I think your 'workaround' is better.

Here's an example that populates the list from 1-19 and then does the check:

set theList to {}

set a to 15

repeat with w from 1 to 19

set end of theList to w

end repeat

theList contains a

Or, the following:

set myRange to {}

set w to "19"

set a to "15"

set {TID, AppleScript'stext item delimiters} to {AppleScript'stext item delimiters, space}

set myRange to text items of (do shell script "echo $(seq 19)")

set AppleScript'stext item delimiters to TID

if a is in myRange then display dialog "In the range!"

Hello

Be careful about the class of values in comparision. E.g.,

"9" ≤ "19" -- false "9" ≤ 19 -- equivalent to "9" <= "19"; false 9 ≤ "19" -- equivalent to 9 <= 19; true 9 ≤ 19 -- true

So, if understand it correctly, your script should have been something like this.

set a to "9" set w to "19" if (0 + a) ≥ 1 and (0 + a) ≤ w then display dialog "In the Range!" end if

Also you may define a handler for range test as follows.

set w to "19" set a to "9" if in_range(0 + a, {1, w}) then display dialog "" & a & " is in range [1, " & w & "]" else display dialog "" & a & " is out of range [1, " & w & "]" end if on in_range(x, {a, b}) (* number or string x : source value number or string a, b : range boundaries, inclusive return boolean : true if x in [a, b], false otherwise * comparisons are based upon class of x e.g., if x is number, x >= a and x <= b are numerical comparisons if x is string, x >= a and x <= b are lexical comparisons *) x ≥ a and x ≤ b end in_range

Regards,

H