question about size of ints in Xcode
A variable declaration is any statement that specifies a variables name and type. The line *int myInt;* certainly does that. A variable definition is a declaration that causes memory to be allocated for the variable. Since the previous statement does cause memory to be allocated for myInt, it does qualify as a definition.
I always thought a definition of a variable was a statement that assigned a value to a variable. If a basic declaration like "int myInt;" does allocate memory for the variable and therefore is a definition, can anyone give me an example of a declaration that does not allocate memory for the variable and therefore is not a definition?
The book goes on, a page or so late, to say this:
Since myInt was declared to be of type int, and since Xcode is currently set to use 4-byte ints, 4 bytes of memory were reserved for myInt. Since we haven't placed a value in those 4 bytes yet, they could contain any value at all. Some compilers place a value of 0 in a newly allocated variable, but others do not. The key is not to depend on a variable being preset to some specific value. If you want a variable to contain a specific value, assign the value to the variable yourself.
First, I know that an int can be different sizes (either 4 bytes or 8 bytes, I think), but what does this depend on? I thought it depended on the compiler, but the above quote makes it sound like it depends on the IDE, Xcode. Which is it?
Second, it said that Xcode is currently set to use 4-byte ints. Does this mean that there is a setting that the user can change to make ints a different size (like 8 bytes), or does it mean that the creators of Xcode currently have it set to use 4-byte ints?
Third, for the part about some compilers giving a newly allocated variable a value of 0, does this apply to Xcode or any of its compilers? I assume not, but I wanted to check.
Thanks for all the help, and have a great weekend!
MacBook, Mac OS X (10.5.8)